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Add assignment 10
This commit is contained in:
33
scripts/grade-10.sh
Executable file
33
scripts/grade-10.sh
Executable file
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#!/usr/bin/env bash
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set -e
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set -uo pipefail
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IFS=$'\n\t'
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# Imports library.
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BASEDIR=$(dirname "$0")
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source $BASEDIR/grade-utils.sh
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RUNNERS=(
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"cargo"
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"cargo --release"
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"cargo_asan"
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"cargo_asan --release"
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"cargo_tsan"
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"cargo_tsan --release"
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)
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# Lints.
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run_linters || exit 1
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# Executes test for each runner.
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for RUNNER in "${RUNNERS[@]}"; do
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echo "Running with $RUNNER..."
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TESTS=("--lib assignment10_grade")
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if [ $(run_tests) -ne 0 ]; then
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exit 1
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fi
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done
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exit 0
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119
src/assignments/assignment10.rs
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119
src/assignments/assignment10.rs
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//! Assignment 10: Iterators (2/2).
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//!
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//! The primary goal of this assignment is to get used to iterators.
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//!
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//! You should fill out the `todo!()` placeholders in such a way that `/scripts/grade-10.sh` works fine.
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//! See `assignment10_grade.rs` and `/scripts/grade-10.sh` for the test script.
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use itertools::*;
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/// Returns the pairs of `(i, j)` where `i < j` and `inner[i] > inner[j]` in increasing order.
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///
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/// For example, the inversions of `[3, 5, 1, 2, 4]` is `[(0, 2), (0, 3), (1, 2), (1, 3), (1, 4)]` because as follows:
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///
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/// - `0 < 2`, `inner[0] = 3 > 1 = inner[2]`
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/// - `0 < 3`, `inner[0] = 3 > 2 = inner[3]`
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/// - `1 < 2`, `inner[1] = 5 > 1 = inner[2]`
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/// - `1 < 3`, `inner[1] = 5 > 2 = inner[3]`
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/// - `1 < 4`, `inner[1] = 5 > 4 = inner[4]`
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///
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/// Consult <https://en.wikipedia.org/wiki/Inversion_(discrete_mathematics)> for more details of inversion.
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pub fn inversion<T: Ord>(inner: Vec<T>) -> Vec<(usize, usize)> {
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todo!()
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}
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/// Represents a node of tree data structure.
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///
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/// Consult <https://en.wikipedia.org/wiki/Tree_(data_structure)> for more details on tree data structure.
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#[derive(Debug)]
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pub enum Node<T> {
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/// Non-leaf node
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///
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/// It contains `(the name of node, list of child nodes)`.
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NonLeaf((T, Vec<Node<T>>)),
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/// Leaf node
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///
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/// It contains the name of node.
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Leaf(T),
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}
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/// Traverses the tree in preorder.
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///
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/// The algorithm for preorder traversal is as follows:
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///
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/// 1. Visit the root.
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/// 2. If the root is a leaf node, end the traverse.
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/// 3. If the root is a non-leaf node, traverse each subtree from the child nodes.
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///
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/// For example, the result of preorder traversal for the following tree
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///
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/// ```
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/// 1
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/// /|\
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/// 2 3 4
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/// /| /|\
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/// 5 6 7 8 9
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/// ```
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///
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/// which can be represented as
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///
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/// ```
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/// Node::NonLeaf((
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/// 1,
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/// vec![
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/// Node::NonLeaf((2, vec![Node::Leaf(5), Node::Leaf(6)])),
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/// Node::Leaf(3),
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/// Node::NonLeaf((4, vec![Node::Leaf(7), Node::Leaf(8), Node::Leaf(9)])),
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/// ]
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/// ))
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/// ```
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///
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/// is `1 -> 2 -> 5 -> 6 -> 3 -> 4 -> 7 -> 8 -> 9`.
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pub fn traverse_preorder<T>(root: Node<T>) -> Vec<T> {
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todo!()
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}
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/// File
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#[derive(Debug)]
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pub enum File {
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/// Directory
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///
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/// It contains `(name of directory, list of files under the directory)`
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///
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/// The size of a directory is the sum of the sizes of its sub-files.
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Directory(String, Vec<File>),
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/// Data
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///
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/// It contains `(name of data, size of data)`
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Data(String, usize),
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}
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/// Given a file, summarize all subfiles and sizes in ascending order of size.
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///
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/// - Its behaviour is the same as the `du | sort -h` command on Linux.
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/// - If the file size is the same, sort it by name.
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/// - Assume that there are no duplicate file names.
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///
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/// # Example
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///
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/// Input:
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///
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/// ```txt
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/// root (Directory)
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/// |
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/// |__a (Directory)
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/// | |__a1 (Data, size: 1)
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/// | |__a2 (Data, size: 3)
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/// |
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/// |__b (Directory)
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/// | |__b1 (Data, size: 3)
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/// | |__b2 (Data, size: 15)
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/// |
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/// |__c (Data, size: 8)
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/// ```
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///
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/// Output: `[("a1", 1), ("a2", 3), ("b1", 3), ("a", 4), ("c", 8), ("b2", 15), ("b", 18), ("root", 30)]`
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pub fn du_sort(root: &File) -> Vec<(&str, usize)> {
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todo!()
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}
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123
src/assignments/assignment10_grade.rs
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123
src/assignments/assignment10_grade.rs
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@@ -0,0 +1,123 @@
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#[cfg(test)]
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mod test {
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use super::super::assignment10::*;
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#[test]
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fn test_inversion() {
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assert_eq!(inversion(vec![3, 5, 4]), vec![(1, 2)]);
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assert_eq!(inversion(vec!["c", "a", "b", "d"]), vec![(0, 1), (0, 2)]);
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assert_eq!(
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inversion(vec![2, 5, 4, 6, 3, 1]),
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vec![
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(0, 5),
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(1, 2),
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(1, 4),
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(1, 5),
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(2, 4),
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(2, 5),
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(3, 4),
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(3, 5),
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(4, 5)
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]
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);
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}
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#[test]
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fn test_traverse_preorder() {
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let root = Node::NonLeaf((
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1,
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vec![
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Node::NonLeaf((2, vec![Node::Leaf(5), Node::Leaf(6)])),
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Node::Leaf(3),
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Node::NonLeaf((4, vec![Node::Leaf(7), Node::Leaf(8), Node::Leaf(9)])),
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],
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));
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assert_eq!(traverse_preorder(root), vec![1, 2, 5, 6, 3, 4, 7, 8, 9]);
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}
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#[test]
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fn test_du_sort() {
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let rootfile = File::Directory(
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"root".to_string(),
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vec![
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File::Directory(
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"a".to_string(),
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vec![
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File::Data("a1".to_string(), 1),
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File::Data("a2".to_string(), 3),
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],
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),
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File::Directory(
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"b".to_string(),
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vec![
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File::Data("b1".to_string(), 3),
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File::Data("b2".to_string(), 15),
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],
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),
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File::Data("c".to_string(), 8),
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],
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);
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assert_eq!(
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du_sort(&rootfile),
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vec![
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("a1", 1),
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("a2", 3),
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("b1", 3),
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("a", 4),
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("c", 8),
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("b2", 15),
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("b", 18),
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("root", 1 + 3 + 3 + 15 + 8)
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]
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);
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let rootfile = File::Directory(
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"root".to_string(),
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vec![
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File::Directory(
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"a".to_string(),
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vec![
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File::Data("a1".to_string(), 1),
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File::Data("a2".to_string(), 3),
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File::Directory(
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"a3".to_string(),
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vec![
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File::Data("a31".to_string(), 1),
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File::Data("a32".to_string(), 3),
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File::Data("a33".to_string(), 6),
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],
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),
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],
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),
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File::Directory(
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"b".to_string(),
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vec![
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File::Data("b1".to_string(), 3),
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File::Data("b2".to_string(), 15),
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],
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),
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File::Data("c".to_string(), 16),
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],
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);
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assert_eq!(
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du_sort(&rootfile),
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vec![
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("a1", 1),
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("a31", 1),
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("a2", 3),
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("a32", 3),
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("b1", 3),
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("a33", 6),
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("a3", 10),
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("a", 14),
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("b2", 15),
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("c", 16),
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("b", 18),
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("root", 48)
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]
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);
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}
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}
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@@ -22,3 +22,5 @@ pub mod assignment08;
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mod assignment08_grade;
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pub mod assignment09;
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mod assignment09_grade;
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pub mod assignment10;
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mod assignment10_grade;
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